Question 31 asks for the output of a given pseudo code. The pseudo code initializes a variable $B$ to 1. Then, it iterates through a loop where $A$ goes from 2 to 8 with a step of 2. Inside the loop, $B$ is updated by adding $A$ to it ($B = B + A$), and then the value of $B$ is displayed.

1. Problem Description

Question 31 asks for the output of a given pseudo code. The pseudo code initializes a variable $B$ to

1. Then, it iterates through a loop where $A$ goes from 2 to 8 with a step of

2. Inside the loop, $B$ is updated by adding $A$ to it ($B = B + A$), and then the value of $B$ is displayed.

2. Solution Steps

First, initialize $B = 1$.

The loop runs for $A = 2, 4, 6, 8$.

- When $A = 2$: $B = B + A = 1 + 2 = 3$. Display $B$, which is

3. - When $A = 4$: $B = B + A = 3 + 4 = 7$. Display $B$, which is

7. - When $A = 6$: $B = B + A = 7 + 6 = 13$. Display $B$, which is

1

3. - When $A = 8$: $B = B + A = 13 + 8 = 21$. Display $B$, which is

2

1.

So, the output is 3, 7, 13,

2

1.

3. Final Answer

(4) 3, 7, 13, 21