The problem asks us to identify which of the given ordered pairs $(x, y)$ satisfy the equation $3x + 7y = -12$.

AlgebraLinear EquationsSubstitutionOrdered Pairs
2025/5/12

1. Problem Description

The problem asks us to identify which of the given ordered pairs (x,y)(x, y) satisfy the equation 3x+7y=123x + 7y = -12.

2. Solution Steps

We need to substitute each ordered pair into the equation 3x+7y=123x + 7y = -12 and check if the equation holds true.
* Check (6, 0):
3(6)+7(0)=18+0=183(6) + 7(0) = 18 + 0 = 18. Since 181218 \neq -12, (6, 0) is not a solution.
* Check (-6, 7):
3(6)+7(7)=18+49=313(-6) + 7(7) = -18 + 49 = 31. Since 311231 \neq -12, (-6, 7) is not a solution.
* Check (-4, 0):
3(4)+7(0)=12+0=123(-4) + 7(0) = -12 + 0 = -12. Since 12=12-12 = -12, (-4, 0) is a solution.
* Check (3, -3):
3(3)+7(3)=921=123(3) + 7(-3) = 9 - 21 = -12. Since 12=12-12 = -12, (3, -3) is a solution.
* Check (7, 6):
3(7)+7(6)=21+42=633(7) + 7(6) = 21 + 42 = 63. Since 631263 \neq -12, (7, 6) is not a solution.
* Check (0, 7):
3(0)+7(7)=0+49=493(0) + 7(7) = 0 + 49 = 49. Since 491249 \neq -12, (0, 7) is not a solution.

3. Final Answer

The ordered pairs that represent points on the graph of the equation are (-4, 0) and (3, -3).

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