The problem asks us to find the values of the variables y, t, w, and m in the given proportions.

AlgebraProportionsSolving EquationsRatios
2025/5/12

1. Problem Description

The problem asks us to find the values of the variables y, t, w, and m in the given proportions.

2. Solution Steps

a. We are given the proportion 10:y=2:310 : y = 2 : 3.
This can be written as 10y=23\frac{10}{y} = \frac{2}{3}.
Cross-multiplying, we get 2y=10×3=302y = 10 \times 3 = 30.
Dividing by 2, we get y=302=15y = \frac{30}{2} = 15.
b. We are given the proportion 20:25=t:520 : 25 = t : 5.
This can be written as 2025=t5\frac{20}{25} = \frac{t}{5}.
Cross-multiplying, we get 25t=20×5=10025t = 20 \times 5 = 100.
Dividing by 25, we get t=10025=4t = \frac{100}{25} = 4.
c. We are given the proportion y:15=9:45y : 15 = 9 : 45.
This can be written as y15=945\frac{y}{15} = \frac{9}{45}.
Cross-multiplying, we get 45y=15×9=13545y = 15 \times 9 = 135.
Dividing by 45, we get y=13545=3y = \frac{135}{45} = 3.
d. We are given the proportion 2:w=10:52 : w = 10 : 5.
This can be written as 2w=105\frac{2}{w} = \frac{10}{5}.
Cross-multiplying, we get 10w=2×5=1010w = 2 \times 5 = 10.
Dividing by 10, we get w=1010=1w = \frac{10}{10} = 1.
e. We are given the proportion 72:27=8:m72 : 27 = 8 : m.
This can be written as 7227=8m\frac{72}{27} = \frac{8}{m}.
Cross-multiplying, we get 72m=27×8=21672m = 27 \times 8 = 216.
Dividing by 72, we get m=21672=3m = \frac{216}{72} = 3.

3. Final Answer

a. y=15y = 15
b. t=4t = 4
c. y=3y = 3
d. w=1w = 1
e. m=3m = 3

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