The problem requires adding two polynomials: $(2y^2 - 3y + 5)$ and $(y^2 + 3y - 4)$.

1. Problem Description

The problem requires adding two polynomials: $(2y^2 - 3y + 5)$ and $(y^2 + 3y - 4)$.

2. Solution Steps

To add the two polynomials, we combine like terms.

$2y^2$ and $y^2$ are like terms.

$-3y$ and $+3y$ are like terms.

$+5$ and $-4$ are like terms.

$(2y^2 - 3y + 5) + (y^2 + 3y - 4)$

$= 2y^2 + y^2 - 3y + 3y + 5 - 4$

$= (2+1)y^2 + (-3+3)y + (5-4)$

$= 3y^2 + 0y + 1$

$= 3y^2 + 1$

3. Final Answer

$3y^2 + 1$