The problem asks to find how many times the advertising cost of "Service/Leisure" in 2002 is compared to the advertising cost of "Home Appliances/AV Equipment" in 2002. The answer needs to be chosen from the given options: 2.4, 2.8, 3.5, 3.8, and 4.7. The provided table contains the advertising costs (in ten million yen) for different categories in the years 1999, 2002, 2005, 2007, and 2008.

1. Problem Description

The problem asks to find how many times the advertising cost of "Service/Leisure" in 2002 is compared to the advertising cost of "Home Appliances/AV Equipment" in

2

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0

2. The answer needs to be chosen from the given options: 2.4, 2.8, 3.5, 3.8, and 4.

7. The provided table contains the advertising costs (in ten million yen) for different categories in the years 1999, 2002, 2005, 2007, and

2

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0

8.

2. Solution Steps

First, identify the advertising cost of "Service/Leisure" in 2002 from the table. According to the table, the advertising cost for "Service/Leisure" in 2002 is 34,965 (ten million yen).

Next, identify the advertising cost of "Home Appliances/AV Equipment" in

2

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2. According to the table, the advertising cost for "Home Appliances/AV Equipment" in 2002 is 12,456 (ten million yen).

Now, calculate the ratio of the two advertising costs.

Ratio = $\frac{\text{Advertising cost of Service/Leisure in 2002}}{\text{Advertising cost of Home Appliances/AV Equipment in 2002}}$

Ratio = $\frac{34965}{12456} \approx 2.807$

Finally, choose the closest option to 2.807 from the given options. The closest option is 2.

8.

3. Final Answer

2. 8倍