A 5 kg object A is placed on a rough surface with a coefficient of friction $\mu = \frac{1}{2}$. It is connected to object B by a light, inextensible string passing over a smooth pulley. We need to find the minimum mass of object B (in kg) required to initiate the movement of the system.

Applied MathematicsPhysicsFrictionNewton's Laws of MotionMechanicsForces
2025/6/26

1. Problem Description

A 5 kg object A is placed on a rough surface with a coefficient of friction μ=12\mu = \frac{1}{2}. It is connected to object B by a light, inextensible string passing over a smooth pulley. We need to find the minimum mass of object B (in kg) required to initiate the movement of the system.

2. Solution Steps

Let mAm_A be the mass of object A and mBm_B be the mass of object B. We are given mA=5m_A = 5 kg and μ=12\mu = \frac{1}{2}. The weight of object A is WA=mAgW_A = m_A g, and the normal force acting on object A is equal to its weight, so N=mAgN = m_A g. The friction force acting on object A is f=μN=μmAgf = \mu N = \mu m_A g.
For the system to start moving, the tension in the string must be greater than or equal to the friction force. The tension in the string is equal to the weight of object B, which is WB=mBgW_B = m_B g.
Therefore, we have mBgμmAgm_B g \ge \mu m_A g.
Dividing both sides by gg, we get:
mBμmAm_B \ge \mu m_A.
Substituting the given values, we have
mB12×5=2.5m_B \ge \frac{1}{2} \times 5 = 2.5 kg.
The minimum mass of object B is therefore 2.5 kg.

3. Final Answer

2. 5

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