The problem consists of solving two sets of inequalities. (1) is a system of inequalities: $8x - 15 < 4x - 35$ $0.3x + 1 > 0.5x - 0.2$ (2) is a compound inequality: $x - 5 < 2x \le 6 - x$

AlgebraInequalitiesLinear InequalitiesCompound InequalitiesSystems of Inequalities
2025/6/26

1. Problem Description

The problem consists of solving two sets of inequalities.
(1) is a system of inequalities:
8x15<4x358x - 15 < 4x - 35
0.3x+1>0.5x0.20.3x + 1 > 0.5x - 0.2
(2) is a compound inequality:
x5<2x6xx - 5 < 2x \le 6 - x

2. Solution Steps

(1) Solving the system of inequalities:
First inequality:
8x15<4x358x - 15 < 4x - 35
8x4x<35+158x - 4x < -35 + 15
4x<204x < -20
x<5x < -5
Second inequality:
0.3x+1>0.5x0.20.3x + 1 > 0.5x - 0.2
1+0.2>0.5x0.3x1 + 0.2 > 0.5x - 0.3x
1.2>0.2x1.2 > 0.2x
0.2x<1.20.2x < 1.2
x<1.20.2x < \frac{1.2}{0.2}
x<6x < 6
Combining the inequalities x<5x < -5 and x<6x < 6, we take the more restrictive condition, which is x<5x < -5.
Therefore, the answer for 30 is -
5.
(2) Solving the compound inequality:
x5<2x6xx - 5 < 2x \le 6 - x
This can be split into two inequalities:
x5<2xx - 5 < 2x and 2x6x2x \le 6 - x
First inequality:
x5<2xx - 5 < 2x
5<2xx-5 < 2x - x
5<x-5 < x
x>5x > -5
Second inequality:
2x6x2x \le 6 - x
2x+x62x + x \le 6
3x63x \le 6
x2x \le 2
Combining the inequalities x>5x > -5 and x2x \le 2, we have 5<x2-5 < x \le 2.
Therefore, the answer for 31-1 is -5, and the answer for 31-2 is
2.

3. Final Answer

30: -5
31-1: -5
31-2: 2

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