The problem asks to find the point on the number line that most closely represents $-\sqrt{8}$. The points on the number line are $j$, $k$, and $l$, located at approximately $-2.9$, $-2.8$, and $-2.7$, respectively.

1. Problem Description

The problem asks to find the point on the number line that most closely represents $-\sqrt{8}$. The points on the number line are $j$, $k$, and $l$, located at approximately $-2.9$, $-2.8$, and $-2.7$, respectively.

2. Solution Steps

First, we need to find the value of $-\sqrt{8}$. We know that $2^2 = 4$ and $3^2 = 9$. Thus, $\sqrt{8}$ is between 2 and

3. Also, $2.8^2 = 7.84$ and $2.9^2 = 8.41$.

Thus, $\sqrt{8}$ is between 2.8 and 2.

9. A closer estimation is to notice that 8 is closer to 7.84 than to 8.41, so $\sqrt{8}$ is closer to 2.8 than to 2.

9.

Let's calculate $\sqrt{8}$ using a calculator: $\sqrt{8} \approx 2.828$.

Therefore, $-\sqrt{8} \approx -2.828$.

Now, we need to find which point on the number line is closest to $-2.828$.

Point $j$ is at $-2.9$. The difference between $-2.9$ and $-2.828$ is $|-2.9 - (-2.828)| = |-2.9 + 2.828| = |-0.072| = 0.072$.

Point $k$ is at $-2.8$. The difference between $-2.8$ and $-2.828$ is $|-2.8 - (-2.828)| = |-2.8 + 2.828| = |0.028| = 0.028$.

Point $l$ is at $-2.7$. The difference between $-2.7$ and $-2.828$ is $|-2.7 - (-2.828)| = |-2.7 + 2.828| = |0.128| = 0.128$.

Since $0.028 < 0.072 < 0.128$, the point $k$ is closest to $-\sqrt{8}$.

3. Final Answer

B. k