The problem asks us to simplify the given fractions to their lowest terms. We have 6 fractions to simplify: a) $-\frac{18}{30}$ b) $\frac{16}{48}$ c) $-\frac{7}{21}$ d) $-\frac{162}{24}$ e) $-2\frac{5}{75}$ f) $3\frac{24}{36}$

1. Problem Description

The problem asks us to simplify the given fractions to their lowest terms. We have 6 fractions to simplify:

a) $-\frac{18}{30}$

b) $\frac{16}{48}$

c) $-\frac{7}{21}$

d) $-\frac{162}{24}$

e) $-2\frac{5}{75}$

f) $3\frac{24}{36}$

2. Solution Steps

a) $-\frac{18}{30}$: Both 18 and 30 are divisible by

6. $-\frac{18}{30} = -\frac{18 \div 6}{30 \div 6} = -\frac{3}{5}$

b) $\frac{16}{48}$: Both 16 and 48 are divisible by

1

6. $\frac{16}{48} = \frac{16 \div 16}{48 \div 16} = \frac{1}{3}$

c) $-\frac{7}{21}$: Both 7 and 21 are divisible by

7. $-\frac{7}{21} = -\frac{7 \div 7}{21 \div 7} = -\frac{1}{3}$

d) $-\frac{162}{24}$: Both 162 and 24 are divisible by

2. $-\frac{162}{24} = -\frac{162 \div 2}{24 \div 2} = -\frac{81}{12}$.

Both 81 and 12 are divisible by

3. $-\frac{81}{12} = -\frac{81 \div 3}{12 \div 3} = -\frac{27}{4}$

e) $-2\frac{5}{75}$: First, simplify the fraction part $\frac{5}{75}$. Both 5 and 75 are divisible by

5. $\frac{5}{75} = \frac{5 \div 5}{75 \div 5} = \frac{1}{15}$.

So, $-2\frac{5}{75} = -2\frac{1}{15}$.

f) $3\frac{24}{36}$: First, simplify the fraction part $\frac{24}{36}$. Both 24 and 36 are divisible by

1

2. $\frac{24}{36} = \frac{24 \div 12}{36 \div 12} = \frac{2}{3}$.

So, $3\frac{24}{36} = 3\frac{2}{3}$.

3. Final Answer

a) $-\frac{3}{5}$

b) $\frac{1}{3}$

c) $-\frac{1}{3}$

d) $-\frac{27}{4}$

e) $-2\frac{1}{15}$

f) $3\frac{2}{3}$