The problem states that an unregulated electric company is a monopolist and faces a demand curve of $Q = 100 - 50P$. The marginal cost is constant and equal to 1. We need to find the profit-maximizing price.

Applied MathematicsMicroeconomicsMonopolyDemand CurveMarginal CostMarginal RevenueProfit MaximizationCalculus (Differentiation)
2025/7/1

1. Problem Description

The problem states that an unregulated electric company is a monopolist and faces a demand curve of Q=10050PQ = 100 - 50P. The marginal cost is constant and equal to

1. We need to find the profit-maximizing price.

2. Solution Steps

First, we need to express the inverse demand function, which expresses price as a function of quantity. From Q=10050PQ = 100 - 50P, we can solve for PP:
50P=100Q50P = 100 - Q
P=100Q50P = \frac{100 - Q}{50}
P=2150QP = 2 - \frac{1}{50}Q
The total revenue (TR) is the product of price and quantity:
TR=P×Q=(2150Q)Q=2Q150Q2TR = P \times Q = (2 - \frac{1}{50}Q)Q = 2Q - \frac{1}{50}Q^2
The marginal revenue (MR) is the derivative of total revenue with respect to quantity:
MR=d(TR)dQ=2250Q=2125QMR = \frac{d(TR)}{dQ} = 2 - \frac{2}{50}Q = 2 - \frac{1}{25}Q
To maximize profit, the monopolist will produce where marginal revenue equals marginal cost (MC). In this case, MC=1MC = 1.
MR=MCMR = MC
2125Q=12 - \frac{1}{25}Q = 1
125Q=1\frac{1}{25}Q = 1
Q=25Q = 25
Now, we substitute this quantity back into the inverse demand function to find the profit-maximizing price:
P=2150Q=2150(25)=22550=212=20.5=1.5P = 2 - \frac{1}{50}Q = 2 - \frac{1}{50}(25) = 2 - \frac{25}{50} = 2 - \frac{1}{2} = 2 - 0.5 = 1.5

3. Final Answer

The profit-maximizing price is 1.
5.

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