The problem consists of several equations. We need to solve for the variable $a$ in each equation. I will solve equation 32.

AlgebraLinear EquationsSolving Equations
2025/7/1

1. Problem Description

The problem consists of several equations. We need to solve for the variable aa in each equation. I will solve equation
3
2.

2. Solution Steps

We are given the equation 52a=15 - 2a = 1.
First, subtract 5 from both sides of the equation:
52a5=155 - 2a - 5 = 1 - 5
2a=4-2a = -4
Next, divide both sides by -2:
2a2=42\frac{-2a}{-2} = \frac{-4}{-2}
a=2a = 2

3. Final Answer

a=2a = 2

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