The image contains several fraction multiplication problems. We need to solve problems number 2 and 4. Problem 2 is $\frac{7}{4} \times \frac{5}{6}$. Problem 4 is $6 \times \frac{2}{3}$.

ArithmeticFractionsMultiplicationFraction MultiplicationSimplification
2025/7/3

1. Problem Description

The image contains several fraction multiplication problems. We need to solve problems number 2 and

4. Problem 2 is $\frac{7}{4} \times \frac{5}{6}$.

Problem 4 is 6×236 \times \frac{2}{3}.

2. Solution Steps

For problem 2, we multiply the numerators and the denominators:
74×56=7×54×6\frac{7}{4} \times \frac{5}{6} = \frac{7 \times 5}{4 \times 6}
7×54×6=3524\frac{7 \times 5}{4 \times 6} = \frac{35}{24}
For problem 4, we can rewrite 6 as a fraction 61\frac{6}{1}:
6×23=61×236 \times \frac{2}{3} = \frac{6}{1} \times \frac{2}{3}
Then, multiply the numerators and the denominators:
61×23=6×21×3\frac{6}{1} \times \frac{2}{3} = \frac{6 \times 2}{1 \times 3}
6×21×3=123\frac{6 \times 2}{1 \times 3} = \frac{12}{3}
Simplify the fraction:
123=4\frac{12}{3} = 4

3. Final Answer

The answer to problem 2 is 3524\frac{35}{24}.
The answer to problem 4 is 44.

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