We are given a right triangle FGH, where angle G is a right angle. The length of the side FH is 98, and the length of the side GH is 56. We need to find the measure of angle F, which is labeled as $x$.

GeometryTrigonometryRight TrianglesSineAnglesArctangent
2025/4/1

1. Problem Description

We are given a right triangle FGH, where angle G is a right angle. The length of the side FH is 98, and the length of the side GH is
5

6. We need to find the measure of angle F, which is labeled as $x$.

2. Solution Steps

Since we have a right triangle, we can use trigonometric ratios to find the angle xx. We know the lengths of the side opposite to angle F (GH) and the hypotenuse (FH). Therefore, we can use the sine function:
sin(x)=oppositehypotenusesin(x) = \frac{opposite}{hypotenuse}
sin(x)=GHFHsin(x) = \frac{GH}{FH}
sin(x)=5698sin(x) = \frac{56}{98}
To find the angle xx, we need to take the inverse sine (arcsin) of 5698\frac{56}{98}:
x=arcsin(5698)x = arcsin(\frac{56}{98})
x=arcsin(0.5714285714)x = arcsin(0.5714285714)
x34.8x \approx 34.8^{\circ}

3. Final Answer

x34.8x \approx 34.8 degrees.

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