Given that $m\angle 9 = 75^{\circ}$, find the measure of the following angles: $\angle 3$, $\angle 5$, $\angle 6$, $\angle 8$, $\angle 11$, and $\angle 12$. Lines $l$, $m$, and $n$ are parallel. Line $t$ is a transversal.

GeometryAnglesParallel LinesTransversalsCorresponding AnglesVertical AnglesSupplementary Angles
2025/4/1

1. Problem Description

Given that m9=75m\angle 9 = 75^{\circ}, find the measure of the following angles: 3\angle 3, 5\angle 5, 6\angle 6, 8\angle 8, 11\angle 11, and 12\angle 12. Lines ll, mm, and nn are parallel. Line tt is a transversal.

2. Solution Steps

First, we find the measure of 3\angle 3. Since lines ll, mm and nn are parallel, 3\angle 3 and 7\angle 7 are corresponding angles, and 7\angle 7 and 11\angle 11 are corresponding angles. Also 9\angle 9 and 11\angle 11 are vertical angles. Vertical angles are equal, so m9=m11=75m\angle 9 = m\angle 11 = 75^{\circ}.
Also since lines ll, mm and nn are parallel, m3=m7m\angle 3 = m\angle 7.
Since 7\angle 7 and 11\angle 11 are corresponding angles, m7=m11m\angle 7=m\angle 11. Therefore, m3=m11m\angle 3=m\angle 11.
Thus, m3=75m\angle 3 = 75^{\circ}.
Next, we find the measure of 5\angle 5. Since m9=75m\angle 9=75^{\circ}, then m10=18075=105m\angle 10=180^{\circ}-75^{\circ}=105^{\circ}.
Corresponding angles are congruent, so m6=m10=105m\angle 6=m\angle 10=105^{\circ} and m5=m9=75m\angle 5=m\angle 9 = 75^{\circ}.
Therefore m5=75m\angle 5 = 75^{\circ}.
Next, we find the measure of 6\angle 6. As mentioned before, m6=105m\angle 6 = 105^{\circ}.
Next, we find the measure of 8\angle 8. Since 8\angle 8 and 5\angle 5 are vertical angles, m8=m5=75m\angle 8 = m\angle 5 = 75^{\circ}.
Next, we find the measure of 11\angle 11. As mentioned before, since 9\angle 9 and 11\angle 11 are vertical angles, m11=m9=75m\angle 11 = m\angle 9 = 75^{\circ}.
Finally, we find the measure of 12\angle 12. Since 11\angle 11 and 12\angle 12 form a straight line, they are supplementary. Therefore, m11+m12=180m\angle 11 + m\angle 12 = 180^{\circ}.
Since m11=75m\angle 11 = 75^{\circ}, m12=18075=105m\angle 12 = 180^{\circ} - 75^{\circ} = 105^{\circ}.

3. Final Answer

m3=75m\angle 3 = 75^{\circ}
m5=75m\angle 5 = 75^{\circ}
m6=105m\angle 6 = 105^{\circ}
m8=75m\angle 8 = 75^{\circ}
m11=75m\angle 11 = 75^{\circ}
m12=105m\angle 12 = 105^{\circ}

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