The problem is to solve the system of linear equations: $4x + 3y = -4$ $-5x + y = 5$

1. Problem Description

The problem is to solve the system of linear equations:

$4x + 3y = -4$

$-5x + y = 5$

2. Solution Steps

We can solve this system of equations using either substitution or elimination. I will use the substitution method.

First, solve the second equation for $y$:

$y = 5x + 5$

Now, substitute this expression for $y$ into the first equation:

$4x + 3(5x + 5) = -4$

Distribute the 3:

$4x + 15x + 15 = -4$

Combine like terms:

$19x + 15 = -4$

Subtract 15 from both sides:

$19x = -19$

Divide by 19:

$x = -1$

Now, substitute $x = -1$ back into the equation $y = 5x + 5$:

$y = 5(-1) + 5$

$y = -5 + 5$

$y = 0$

Therefore, the solution to the system of equations is $x = -1$ and $y = 0$.

3. Final Answer

$x = -1$ and $y = 0$