The problem asks to calculate the dot product of two vectors $\vec{a}$ and $\vec{b}$, given that the angle between them is 180 degrees, $|\vec{a}| = 2$ and $|\vec{b}| = 5$.

GeometryVectorsDot ProductAngle between vectorsTrigonometry
2025/7/12

1. Problem Description

The problem asks to calculate the dot product of two vectors a\vec{a} and b\vec{b}, given that the angle between them is 180 degrees, a=2|\vec{a}| = 2 and b=5|\vec{b}| = 5.

2. Solution Steps

We use the formula for the dot product of two vectors:
ab=abcosθ\vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos{\theta}
where θ\theta is the angle between the two vectors. In this case, θ=180\theta = 180^{\circ}. We know that cos180=1\cos{180^{\circ}} = -1.
Thus,
ab=abcos180=(2)(5)(1)=10\vec{a} \cdot \vec{b} = |\vec{a}| |\vec{b}| \cos{180^{\circ}} = (2)(5)(-1) = -10

3. Final Answer

ab=10\vec{a} \cdot \vec{b} = -10

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