The homework assignment 6.8 contains four problems: Problem 5: Write "two hundred and twelve thousand" as a numeral. Problem 6: Write 40270 in expanded form. Problem 7: Write $5 \times 10000 + 2 \times 100 + 3 \times 10 + 8$ in its simplest form. Problem 8: How many days from 25th December 2013 to 25th February 2014?

1. Problem Description

The homework assignment 6.8 contains four problems:

Problem 5: Write "two hundred and twelve thousand" as a numeral.

Problem 6: Write 40270 in expanded form.

Problem 7: Write $5 \times 10000 + 2 \times 100 + 3 \times 10 + 8$ in its simplest form.

Problem 8: How many days from 25th December 2013 to 25th February 2014?

2. Solution Steps

Problem 5:

"Two hundred and twelve thousand" is written as 212,

0

0

0.

Problem 6:

40270 in expanded form is $4 \times 10000 + 0 \times 1000 + 2 \times 100 + 7 \times 10 + 0 \times 1$.

Problem 7:

$5 \times 10000 + 2 \times 100 + 3 \times 10 + 8$

$= 50000 + 200 + 30 + 8$

$= 50238$

Problem 8:

The number of days from 25th December 2013 to 25th February 2014:

From 25th December 2013 to 31st December 2013, there are $31 - 25 + 1 = 6$ days. But since we are looking for the number of days *from* 25th, we subtract 1 to get $31-25 = 6$ days.

In January 2014, there are 31 days.

From 1st February 2014 to 25th February 2014, there are 25 days.

Total number of days = $6 + 31 + 25 = 62$ days.

3. Final Answer

Problem 5: 212,000

Problem 6: $4 \times 10000 + 0 \times 1000 + 2 \times 100 + 7 \times 10 + 0 \times 1$

Problem 7: 50238

Problem 8: 62 days