The problem is to solve the following system of equations: $7x = -3 + 10y$ $9 - 3x = 6y$

AlgebraSystems of EquationsLinear EquationsSubstitution
2025/4/3

1. Problem Description

The problem is to solve the following system of equations:
7x=3+10y7x = -3 + 10y
93x=6y9 - 3x = 6y

2. Solution Steps

First, we can isolate xx in the second equation:
93x=6y9 - 3x = 6y
96y=3x9 - 6y = 3x
3x=96y3x = 9 - 6y
x=(96y)/3x = (9 - 6y) / 3
x=32yx = 3 - 2y
Now, substitute this expression for xx into the first equation:
7x=3+10y7x = -3 + 10y
7(32y)=3+10y7(3 - 2y) = -3 + 10y
2114y=3+10y21 - 14y = -3 + 10y
21+3=10y+14y21 + 3 = 10y + 14y
24=24y24 = 24y
y=1y = 1
Now, substitute the value of yy back into the expression for xx:
x=32yx = 3 - 2y
x=32(1)x = 3 - 2(1)
x=32x = 3 - 2
x=1x = 1
Therefore, the solution to the system of equations is x=1x = 1 and y=1y = 1.

3. Final Answer

x=1x = 1
y=1y = 1