Simplify the expression $p^2 \cdot 3p^{-3}$.

AlgebraExponentsSimplificationAlgebraic Expressions
2025/4/3

1. Problem Description

Simplify the expression p23p3p^2 \cdot 3p^{-3}.

2. Solution Steps

First, we can rewrite the expression by grouping the constant term and the pp terms together:
p23p3=3p2p3p^2 \cdot 3p^{-3} = 3 \cdot p^2 \cdot p^{-3}
Next, we can use the property of exponents that states when multiplying terms with the same base, we add the exponents: aman=am+na^m \cdot a^n = a^{m+n}. In this case, a=pa=p, m=2m=2, and n=3n=-3. Therefore:
p2p3=p2+(3)=p1p^2 \cdot p^{-3} = p^{2+(-3)} = p^{-1}
Substituting this back into the expression, we have:
3p2p3=3p13 \cdot p^2 \cdot p^{-3} = 3 \cdot p^{-1}
Finally, we can rewrite p1p^{-1} as 1p\frac{1}{p}:
3p1=31p=3p3p^{-1} = 3 \cdot \frac{1}{p} = \frac{3}{p}

3. Final Answer

The simplified expression is 3p\frac{3}{p}.

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