The problem asks us to evaluate the expression $\sqrt{\frac{2067}{3.48 \times 53.8}}$ using a mathematical table (presumably a logarithm table).

ArithmeticLogarithmsExponentsCalculationSquare Root
2025/7/16

1. Problem Description

The problem asks us to evaluate the expression 20673.48×53.8\sqrt{\frac{2067}{3.48 \times 53.8}} using a mathematical table (presumably a logarithm table).

2. Solution Steps

Let x=20673.48×53.8x = \sqrt{\frac{2067}{3.48 \times 53.8}}.
Then x2=20673.48×53.8x^2 = \frac{2067}{3.48 \times 53.8}.
Taking the logarithm of both sides (base 10), we have:
2log10(x)=log10(2067)log10(3.48)log10(53.8)2\log_{10}(x) = \log_{10}(2067) - \log_{10}(3.48) - \log_{10}(53.8)
log10(x)=12[log10(2067)log10(3.48)log10(53.8)]\log_{10}(x) = \frac{1}{2}[\log_{10}(2067) - \log_{10}(3.48) - \log_{10}(53.8)]
We need to approximate the logarithms using a logarithm table. Since we don't have access to a physical table, we will use a calculator instead.
log10(2067)3.3153\log_{10}(2067) \approx 3.3153
log10(3.48)0.5416\log_{10}(3.48) \approx 0.5416
log10(53.8)1.7308\log_{10}(53.8) \approx 1.7308
Substituting these values into the equation:
log10(x)=12[3.31530.54161.7308]\log_{10}(x) = \frac{1}{2}[3.3153 - 0.5416 - 1.7308]
log10(x)=12[3.31532.2724]\log_{10}(x) = \frac{1}{2}[3.3153 - 2.2724]
log10(x)=12[1.0429]\log_{10}(x) = \frac{1}{2}[1.0429]
log10(x)=0.52145\log_{10}(x) = 0.52145
Now, we need to find the antilogarithm of 0.521450.52145, which is 100.5214510^{0.52145}.
x=100.521453.322x = 10^{0.52145} \approx 3.322

3. Final Answer

The final answer is approximately 3.322.

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