We are given the equation $F = 1.8C + 32$, and we need to solve for $C$. This means we need to isolate $C$ on one side of the equation.

AlgebraLinear EquationsEquation SolvingVariable IsolationFormula Manipulation
2025/4/3

1. Problem Description

We are given the equation F=1.8C+32F = 1.8C + 32, and we need to solve for CC. This means we need to isolate CC on one side of the equation.

2. Solution Steps

Step 1: Subtract 32 from both sides of the equation to isolate the term with CC.
F32=1.8C+3232F - 32 = 1.8C + 32 - 32
F32=1.8CF - 32 = 1.8C
Step 2: Divide both sides of the equation by 1.8 to solve for CC.
F321.8=1.8C1.8\frac{F - 32}{1.8} = \frac{1.8C}{1.8}
F321.8=C\frac{F - 32}{1.8} = C
Step 3: Express 1.8 as a fraction. 1.8=1810=951.8 = \frac{18}{10} = \frac{9}{5}.
C=F329/5C = \frac{F - 32}{9/5}
C=5(F32)9C = \frac{5(F - 32)}{9}
C=59(F32)C = \frac{5}{9}(F - 32)

3. Final Answer

C=5(F32)9C = \frac{5(F - 32)}{9} or C=F321.8C = \frac{F-32}{1.8} or C=59(F32)C = \frac{5}{9}(F - 32)