The problem contains three different math problems. First, we need to find the missing numbers in the following equations: $ \boxed{} + 85 = 200 $ $ 4 \times \boxed{} = 120 $ $ 120 - 51 = \boxed{} $ Second, we need to determine which of the given numbers (84, 87, 72, 76, and 90) round to 80 when rounded to the nearest 10.

1. Problem Description

The problem contains three different math problems.

First, we need to find the missing numbers in the following equations:

$\boxed{} + 85 = 200$

$4 \times \boxed{} = 120$

$120 - 51 = \boxed{}$

Second, we need to determine which of the given numbers (84, 87, 72, 76, and 90) round to 80 when rounded to the nearest

1

0.

2. Solution Steps

First Equation:

To find the missing number in $\boxed{} + 85 = 200$, we subtract 85 from

2

0

0. $ 200 - 85 = 115 $

So, the missing number is

1

1

5.

Second Equation:

To find the missing number in $4 \times \boxed{} = 120$, we divide 120 by

4. $ 120 \div 4 = 30 $

So, the missing number is

3

0.

Third Equation:

To find the missing number in $120 - 51 = \boxed{}$, we subtract 51 from

1

2

0. $ 120 - 51 = 69 $

So, the missing number is

6

9.

Rounding to the Nearest 10:

84 rounds to

8

0. 87 rounds to

9

0. 72 rounds to

7

0. 76 rounds to

8

0. 90 rounds to

9

0. The numbers that round to 80 are 84 and

7

6.

3. Final Answer

Missing numbers:

$115 + 85 = 200$

$4 \times 30 = 120$

$120 - 51 = 69$

Numbers that round to 80: 84 and

7

6.