The problem asks us to fill in the missing numbers in three equations and identify which numbers round to 80 when rounded to the nearest 10.

ArithmeticAdditionSubtractionMultiplicationDivisionRounding
2025/4/4

1. Problem Description

The problem asks us to fill in the missing numbers in three equations and identify which numbers round to 80 when rounded to the nearest
1
0.

2. Solution Steps

First Equation:
We have +85=200\Box + 85 = 200. To find the missing number, we subtract 85 from
2
0

0. $200 - 85 = 115$.

So the missing number is
1
1
5.
Second Equation:
We have 4×=1204 \times \Box = 120. To find the missing number, we divide 120 by

4. $120 \div 4 = 30$.

So the missing number is
3
0.
Third Equation:
We have 12051=120 - 51 = \Box. To find the missing number, we subtract 51 from
1
2

0. $120 - 51 = 69$.

So the missing number is
6
9.
Rounding to the nearest 10:
We need to determine which of the following numbers, 84, 87, 72, 76, and 90, round to
8

0. - 84: Since the ones digit is 4, which is less than 5, we round down to

8

0. - 87: Since the ones digit is 7, which is greater than or equal to 5, we round up to

9

0. - 72: Since the ones digit is 2, which is less than 5, we round down to

7

0. - 76: Since the ones digit is 6, which is greater than or equal to 5, we round up to

8

0. - 90: 90 is already a multiple of 10, so it stays

9
0.
Therefore, 84 and 76 round to
8
0.

3. Final Answer

The missing numbers are: 115, 30,
6

9. The numbers that round to 80 are: 84, 76.

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