We need to solve two problems: Problem 4: $4048 \div 11 = ?$ Problem 5: $21 \times 59 = ?$

1. Problem Description

We need to solve two problems:

Problem 4: $4048 \div 11 = ?$

Problem 5: $21 \times 59 = ?$

2. Solution Steps

Problem 4: $4048 \div 11$

We perform long division.

$40 \div 11 = 3$ with remainder $7$.

So we have $3$ in the hundreds place.

$74 \div 11 = 6$ with remainder $8$.

So we have $6$ in the tens place.

$88 \div 11 = 8$.

So we have $8$ in the ones place.

Therefore $4048 \div 11 = 368$.

Problem 5: $21 \times 59$

We can multiply these two numbers.

$21 \times 59 = 21 \times (60-1) = 21 \times 60 - 21 = 1260 - 21 = 1239$.

Alternatively, we can directly multiply:

21

x 59

----

189

105

----

1239

3. Final Answer

Problem 4: $368$

Problem 5: $1239$