The problem asks us to fill in the missing numbers in a multiplication grid.

ArithmeticMultiplicationGridProblem SolvingBasic Arithmetic
2025/4/4

1. Problem Description

The problem asks us to fill in the missing numbers in a multiplication grid.

2. Solution Steps

Let's analyze the given multiplication grid.
We have the following information:
- 4×5=204 \times 5 = 20
- Row 2, column 1: 3535
- Row 3, column 1: 3030
- Row 1, column 2: 3636
- Row 1, column 3: 3232
- Row 2, column 2: 6363
- Row 2, column 3: 5656
- Row 3, column 2: 5454
- Row 3, column 3: 4848
First, we need to find the missing numbers in the first column.
Let the missing number in row 2, column 1 be xx. We know x×5=35x \times 5 = 35. Dividing both sides by 55, we get x=355=7x = \frac{35}{5} = 7.
Let the missing number in row 3, column 1 be yy. We know y×5=30y \times 5 = 30. Dividing both sides by 55, we get y=305=6y = \frac{30}{5} = 6.
Now we know the first column is 4,7,64, 7, 6.
Next, we need to find the missing numbers in the first row.
Let the missing number in row 1, column 2 be aa. We know 4×a=364 \times a = 36. Dividing both sides by 44, we get a=364=9a = \frac{36}{4} = 9.
Let the missing number in row 1, column 3 be bb. We know 4×b=324 \times b = 32. Dividing both sides by 44, we get b=324=8b = \frac{32}{4} = 8.
Now we know the first row is 5,9,85, 9, 8.
We can verify our answers by checking the rest of the grid.
- 7×9=637 \times 9 = 63
- 7×8=567 \times 8 = 56
- 6×9=546 \times 9 = 54
- 6×8=486 \times 8 = 48
All these are correct.

3. Final Answer

The missing numbers in the multiplication grid are 77, 66 in the first column, and 99, 88 in the first row.

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