The problem asks us to fill in the missing numbers in a multiplication grid.

1. Problem Description

The problem asks us to fill in the missing numbers in a multiplication grid.

2. Solution Steps

Let's analyze the given multiplication grid.

We have the following information:

- $4 \times 5 = 20$

- Row 2, column 1: $35$

- Row 3, column 1: $30$

- Row 1, column 2: $36$

- Row 1, column 3: $32$

- Row 2, column 2: $63$

- Row 2, column 3: $56$

- Row 3, column 2: $54$

- Row 3, column 3: $48$

First, we need to find the missing numbers in the first column.

Let the missing number in row 2, column 1 be $x$. We know $x \times 5 = 35$. Dividing both sides by $5$, we get $x = \frac{35}{5} = 7$.

Let the missing number in row 3, column 1 be $y$. We know $y \times 5 = 30$. Dividing both sides by $5$, we get $y = \frac{30}{5} = 6$.

Now we know the first column is $4, 7, 6$.

Next, we need to find the missing numbers in the first row.

Let the missing number in row 1, column 2 be $a$. We know $4 \times a = 36$. Dividing both sides by $4$, we get $a = \frac{36}{4} = 9$.

Let the missing number in row 1, column 3 be $b$. We know $4 \times b = 32$. Dividing both sides by $4$, we get $b = \frac{32}{4} = 8$.

Now we know the first row is $5, 9, 8$.

We can verify our answers by checking the rest of the grid.

- $7 \times 9 = 63$

- $7 \times 8 = 56$

- $6 \times 9 = 54$

- $6 \times 8 = 48$

All these are correct.

3. Final Answer

The missing numbers in the multiplication grid are $7$, $6$ in the first column, and $9$, $8$ in the first row.