The problem asks us to fill in the missing numbers in two equations and the missing digits in a multiplication problem.

1. Problem Description

The problem asks us to fill in the missing numbers in two equations and the missing digits in a multiplication problem.

2. Solution Steps

First equation: $(3 \times 4) + \Box = 19$. We need to find the number that, when added to $(3 \times 4)$, equals

1

9. $3 \times 4 = 12$.

$12 + \Box = 19$.

$\Box = 19 - 12$.

$\Box = 7$.

Second equation: $(5 \times 5) - \Box = 23$. We need to find the number that, when subtracted from $(5 \times 5)$, equals

2

3. $5 \times 5 = 25$.

$25 - \Box = 23$.

$\Box = 25 - 23$.

$\Box = 2$.

Third problem:

$\Box 4 \Box \times 6 = 2052$

Let the three digit number be $a4b$. We are given $a4b \times 6 = 2052$.

We divide 2052 by 6 to find $a4b$.

$2052 \div 6 = 342$.

Therefore, $a = 3$ and $b = 2$.

3. Final Answer

The missing numbers for the first equation are

7. The missing number for the second equation is

2. The missing digits for the multiplication problem are 3 and 2, making the number

3

4

2.