The problem consists of two parts. First, sort the numbers 9, 17, and 20 based on whether they are prime or not, and then whether they are even or not. Second, Parveen buys 3 bags of peanuts, pays with £2, and receives 80p change. We need to determine the cost of one bag of peanuts in pence.

1. Problem Description

The problem consists of two parts. First, sort the numbers 9, 17, and 20 based on whether they are prime or not, and then whether they are even or not. Second, Parveen buys 3 bags of peanuts, pays with £2, and receives 80p change. We need to determine the cost of one bag of peanuts in pence.

2. Solution Steps

Sorting Numbers:

* 9 is not prime (since $9 = 3 \times 3$) and is not even.

* 17 is prime and is not even.

* 20 is not prime (since $20 = 2 \times 10$) and is even.

Therefore, the correct boxes are:

* Even: 20

* Prime, not even: 17

* Not prime, even: (already filled by 20)

* Not prime, not even: 9

Cost of Peanuts:

* Total amount paid = £2 = 200p

* Change received = 80p

* Total cost of 3 bags = Total amount paid - Change received = $200p - 80p = 120p$

* Cost of one bag = Total cost / Number of bags = $120p / 3 = 40p$

3. Final Answer

* Sorted Numbers:

Even: 20

Prime, not even: 17

Not Prime, not Even: 9

* Cost of one bag of peanuts: 40p