The problem presents six arithmetic problems to solve: 1. $73 \times 4 = ?$ArithmeticMultiplicationAdditionSubtractionDecimal ArithmeticBasic Arithmetic Operations2025/4/41. Problem DescriptionThe problem presents six arithmetic problems to solve:1. $73 \times 4 = ?$2. $2067 + 393 = ?$3. $20 \times 20 = ?$4. $3146 - 200 = ?$5. $1.68 \times 6 = ?$6. $0.034 \div 10 = ?$2. Solution Steps1. $73 \times 4$:73×4=(70×4)+(3×4)=280+12=29273 \times 4 = (70 \times 4) + (3 \times 4) = 280 + 12 = 29273×4=(70×4)+(3×4)=280+12=2922. $2067 + 393$:2067+393=24602067 + 393 = 24602067+393=24603. $20 \times 20$:20×20=40020 \times 20 = 40020×20=4004. $3146 - 200$:3146−200=29463146 - 200 = 29463146−200=29465. $1.68 \times 6$:1.68×6=10.081.68 \times 6 = 10.081.68×6=10.086. $0.034 \div 10$:0.034÷10=0.00340.034 \div 10 = 0.00340.034÷10=0.00343. Final Answer1. $73 \times 4 = 292$2. $2067 + 393 = 2460$3. $20 \times 20 = 400$4. $3146 - 200 = 2946$5. $1.68 \times 6 = 10.08$6. $0.034 \div 10 = 0.0034$