The problem presents six arithmetic problems to solve: 1. $73 \times 4 = ?$

ArithmeticMultiplicationAdditionSubtractionDecimal ArithmeticBasic Arithmetic Operations
2025/4/4

1. Problem Description

The problem presents six arithmetic problems to solve:

1. $73 \times 4 = ?$

2. $2067 + 393 = ?$

3. $20 \times 20 = ?$

4. $3146 - 200 = ?$

5. $1.68 \times 6 = ?$

6. $0.034 \div 10 = ?$

2. Solution Steps

1. $73 \times 4$:

73×4=(70×4)+(3×4)=280+12=29273 \times 4 = (70 \times 4) + (3 \times 4) = 280 + 12 = 292

2. $2067 + 393$:

2067+393=24602067 + 393 = 2460

3. $20 \times 20$:

20×20=40020 \times 20 = 400

4. $3146 - 200$:

3146200=29463146 - 200 = 2946

5. $1.68 \times 6$:

1.68×6=10.081.68 \times 6 = 10.08

6. $0.034 \div 10$:

0.034÷10=0.00340.034 \div 10 = 0.0034

3. Final Answer

1. $73 \times 4 = 292$

2. $2067 + 393 = 2460$

3. $20 \times 20 = 400$

4. $3146 - 200 = 2946$

5. $1.68 \times 6 = 10.08$

6. $0.034 \div 10 = 0.0034$

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