We have four problems to solve: Problem 27: Subtract two fractions: $\frac{3}{10} - \frac{1}{20}$. Problem 28: Divide 725 by 29. Problem 29: Calculate 15% of 440. Problem 30: Multiply 6574 by 31.

ArithmeticFractionsDivisionPercentageMultiplication
2025/4/5

1. Problem Description

We have four problems to solve:
Problem 27: Subtract two fractions: 310120\frac{3}{10} - \frac{1}{20}.
Problem 28: Divide 725 by
2

9. Problem 29: Calculate 15% of

4
4

0. Problem 30: Multiply 6574 by

3
1.

2. Solution Steps

Problem 27:
To subtract the fractions, we need a common denominator. The least common multiple of 10 and 20 is
2

0. So, we rewrite the first fraction with a denominator of

2

0. $\frac{3}{10} = \frac{3 \times 2}{10 \times 2} = \frac{6}{20}$

Now we can subtract:
620120=6120=520\frac{6}{20} - \frac{1}{20} = \frac{6-1}{20} = \frac{5}{20}
Finally, simplify the fraction:
520=14\frac{5}{20} = \frac{1}{4}
Problem 28:
We need to divide 725 by
2

9. $725 \div 29$

29 goes into 72 twice. 2×29=582 \times 29 = 58.
7258=1472 - 58 = 14
Bring down the

5. Now we have

1
4

5. 29 goes into 145 five times. $5 \times 29 = 145$

145145=0145 - 145 = 0
So, 725÷29=25725 \div 29 = 25.
Problem 29:
To calculate 15% of 440, we can multiply 440 by 0.15 or find 10% and 5% separately and add them.
15%×440=0.15×44015\% \times 440 = 0.15 \times 440
0.15×440=660.15 \times 440 = 66
Alternatively:
10%×440=4410\% \times 440 = 44
5%×440=12×10%×440=12×44=225\% \times 440 = \frac{1}{2} \times 10\% \times 440 = \frac{1}{2} \times 44 = 22
15%×440=10%×440+5%×440=44+22=6615\% \times 440 = 10\% \times 440 + 5\% \times 440 = 44 + 22 = 66
Problem 30:
We need to multiply 6574 by
3

1. $6574 \times 31$

First, multiply by 1:
6574×1=65746574 \times 1 = 6574
Next, multiply by 30:
6574×30=6574×3×10=19722×10=1972206574 \times 30 = 6574 \times 3 \times 10 = 19722 \times 10 = 197220
Now, add the two results:
6574+197220=2037946574 + 197220 = 203794

3. Final Answer

Problem 27: 14\frac{1}{4}
Problem 28: 25
Problem 29: 66
Problem 30: 203794

Related problems in "Arithmetic"