We need to solve the following four math problems: Problem 31: $1\frac{4}{5} + \frac{3}{10} = ?$ Problem 32: $1118 \div 43 = ?$ Problem 33: $\frac{3}{5} \div 3 = ?$ Problem 34: $\frac{2}{5} \times 140 = ?$

1. Problem Description

We need to solve the following four math problems:

Problem 31: $1\frac{4}{5} + \frac{3}{10} = ?$

Problem 32: $1118 \div 43 = ?$

Problem 33: $\frac{3}{5} \div 3 = ?$

Problem 34: $\frac{2}{5} \times 140 = ?$

2. Solution Steps

Problem 31: $1\frac{4}{5} + \frac{3}{10}$

First, convert the mixed number to an improper fraction:

$1\frac{4}{5} = \frac{1 \times 5 + 4}{5} = \frac{9}{5}$

Now, we have $\frac{9}{5} + \frac{3}{10}$. To add these fractions, we need a common denominator. The least common multiple of 5 and 10 is

1

0. So, we convert $\frac{9}{5}$ to an equivalent fraction with a denominator of 10:

$\frac{9}{5} = \frac{9 \times 2}{5 \times 2} = \frac{18}{10}$

Now, we can add the fractions:

$\frac{18}{10} + \frac{3}{10} = \frac{18+3}{10} = \frac{21}{10}$

Finally, convert the improper fraction to a mixed number:

$\frac{21}{10} = 2\frac{1}{10}$

Problem 32: $1118 \div 43$

We can use long division to solve this.

$1118 \div 43 = 26$

Problem 33: $\frac{3}{5} \div 3$

To divide a fraction by a whole number, we can multiply the fraction by the reciprocal of the whole number. The reciprocal of 3 is $\frac{1}{3}$.

$\frac{3}{5} \div 3 = \frac{3}{5} \times \frac{1}{3} = \frac{3 \times 1}{5 \times 3} = \frac{3}{15}$

Simplify the fraction:

$\frac{3}{15} = \frac{1}{5}$

Problem 34: $\frac{2}{5} \times 140$

$\frac{2}{5} \times 140 = \frac{2 \times 140}{5} = \frac{280}{5}$

Now, divide 280 by 5:

$280 \div 5 = 56$

3. Final Answer

Problem 31: $2\frac{1}{10}$

Problem 32: $26$

Problem 33: $\frac{1}{5}$

Problem 34: $56$