The problem is to simplify the expression $\sqrt{2} \cdot \sqrt{7}$.

ArithmeticSquare RootsSimplificationRadicals
2025/3/11

1. Problem Description

The problem is to simplify the expression 27\sqrt{2} \cdot \sqrt{7}.

2. Solution Steps

We can use the property of square roots that states ab=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}. Applying this property to the expression, we get:
27=27\sqrt{2} \cdot \sqrt{7} = \sqrt{2 \cdot 7}
27=14\sqrt{2 \cdot 7} = \sqrt{14}
Since 14 has no perfect square factors other than 1, we cannot simplify 14\sqrt{14} any further.

3. Final Answer

The final answer is 14\sqrt{14}.

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