The problem is to convert the following improper fractions to mixed fractions: (1) $\frac{25}{3}$ (2) $\frac{15}{4}$ (3) $\frac{26}{5}$ (4) $\frac{19}{2}$ (5) $\frac{21}{4}$

ArithmeticFractionsImproper FractionsMixed FractionsDivisionNumber Conversion
2025/3/11

1. Problem Description

The problem is to convert the following improper fractions to mixed fractions:
(1) 253\frac{25}{3}
(2) 154\frac{15}{4}
(3) 265\frac{26}{5}
(4) 192\frac{19}{2}
(5) 214\frac{21}{4}

2. Solution Steps

To convert an improper fraction to a mixed fraction, we perform division of the numerator by the denominator. The quotient becomes the whole number part of the mixed fraction, the remainder becomes the numerator of the fractional part, and the denominator stays the same.
(1) 253\frac{25}{3}:
25÷3=825 \div 3 = 8 with a remainder of 11.
So, 253=813\frac{25}{3} = 8\frac{1}{3}.
(2) 154\frac{15}{4}:
15÷4=315 \div 4 = 3 with a remainder of 33.
So, 154=334\frac{15}{4} = 3\frac{3}{4}.
(3) 265\frac{26}{5}:
26÷5=526 \div 5 = 5 with a remainder of 11.
So, 265=515\frac{26}{5} = 5\frac{1}{5}.
(4) 192\frac{19}{2}:
19÷2=919 \div 2 = 9 with a remainder of 11.
So, 192=912\frac{19}{2} = 9\frac{1}{2}.
(5) 214\frac{21}{4}:
21÷4=521 \div 4 = 5 with a remainder of 11.
So, 214=514\frac{21}{4} = 5\frac{1}{4}.

3. Final Answer

(1) 8138\frac{1}{3}
(2) 3343\frac{3}{4}
(3) 5155\frac{1}{5}
(4) 9129\frac{1}{2}
(5) 5145\frac{1}{4}

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