We need to solve the inequality $12 + 6a \le 2(3a + 6)$.

1. Problem Description

We need to solve the inequality $12 + 6a \le 2(3a + 6)$.

2. Solution Steps

First, we distribute the 2 on the right side of the inequality:

$12 + 6a \le 6a + 12$

Next, we subtract $6a$ from both sides:

$12 + 6a - 6a \le 6a + 12 - 6a$

$12 \le 12$

This inequality is always true, regardless of the value of $a$. This means that the solution is all real numbers.

3. Final Answer

All real numbers.