The problem provides a discrete probability distribution and asks to calculate the expected value $E(X)$ (denoted as $M(x)$ in the image), the mode $M_o$, the variance $D(X)$, and the standard deviation $\sigma(X)$. The given data are: $X = \{0, 15, 20\}$ $P(X) = \{0.1, 0.7, 0.2\}$

Probability and StatisticsProbability DistributionExpected ValueModeVarianceStandard DeviationDiscrete Probability
2025/4/8

1. Problem Description

The problem provides a discrete probability distribution and asks to calculate the expected value E(X)E(X) (denoted as M(x)M(x) in the image), the mode MoM_o, the variance D(X)D(X), and the standard deviation σ(X)\sigma(X). The given data are:
X={0,15,20}X = \{0, 15, 20\}
P(X)={0.1,0.7,0.2}P(X) = \{0.1, 0.7, 0.2\}

2. Solution Steps

First, we compute the expected value E(X)E(X) using the formula:
E(X)=xiP(xi)E(X) = \sum x_i P(x_i)
E(X)=(0×0.1)+(15×0.7)+(20×0.2)=0+10.5+4=14.5E(X) = (0 \times 0.1) + (15 \times 0.7) + (20 \times 0.2) = 0 + 10.5 + 4 = 14.5
Next, we find the mode MoM_o, which is the value of XX with the highest probability. In this case, the highest probability is 0.7, which corresponds to X=15X = 15. So, Mo=15M_o = 15.
Then, we calculate the variance D(X)D(X) using the formula:
D(X)=E(X2)[E(X)]2D(X) = E(X^2) - [E(X)]^2
We already have E(X)=14.5E(X) = 14.5. Now, we need to calculate E(X2)E(X^2):
E(X2)=xi2P(xi)E(X^2) = \sum x_i^2 P(x_i)
E(X2)=(02×0.1)+(152×0.7)+(202×0.2)=(0×0.1)+(225×0.7)+(400×0.2)=0+157.5+80=237.5E(X^2) = (0^2 \times 0.1) + (15^2 \times 0.7) + (20^2 \times 0.2) = (0 \times 0.1) + (225 \times 0.7) + (400 \times 0.2) = 0 + 157.5 + 80 = 237.5
Now we can compute D(X)D(X):
D(X)=237.5(14.5)2=237.5210.25=27.25D(X) = 237.5 - (14.5)^2 = 237.5 - 210.25 = 27.25
Finally, we calculate the standard deviation σ(X)\sigma(X) using the formula:
σ(X)=D(X)\sigma(X) = \sqrt{D(X)}
σ(X)=27.255.22\sigma(X) = \sqrt{27.25} \approx 5.22

3. Final Answer

E(X)=14.5E(X) = 14.5
Mo=15M_o = 15
D(X)=27.25D(X) = 27.25
σ(X)5.22\sigma(X) \approx 5.22

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