The problem is to factor the expression $x^3 - 27$.

AlgebraPolynomial FactorizationDifference of CubesAlgebraic Manipulation
2025/4/8

1. Problem Description

The problem is to factor the expression x327x^3 - 27.

2. Solution Steps

We recognize that x327x^3 - 27 is a difference of cubes. We can rewrite the expression as x333x^3 - 3^3.
The difference of cubes formula is:
a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2)
In this case, a=xa = x and b=3b = 3.
Applying the formula:
x333=(x3)(x2+x(3)+32)x^3 - 3^3 = (x - 3)(x^2 + x(3) + 3^2)
x327=(x3)(x2+3x+9)x^3 - 27 = (x - 3)(x^2 + 3x + 9)

3. Final Answer

(x3)(x2+3x+9)(x - 3)(x^2 + 3x + 9)