We need to solve four linear equations for the unknowns $w$, $k$, $t$, and $r$. The equations are: 1. $\frac{w}{-8} - 5 = -6$

AlgebraLinear EquationsSolving Equations
2025/4/8

1. Problem Description

We need to solve four linear equations for the unknowns ww, kk, tt, and rr. The equations are:

1. $\frac{w}{-8} - 5 = -6$

2. $17 = -5k + 2$

3. $\frac{t}{3} + 4 = 10$

4. $-5 = 7 + 3r$

2. Solution Steps

Equation 1: w85=6\frac{w}{-8} - 5 = -6
* Add 5 to both sides:
w85+5=6+5\frac{w}{-8} - 5 + 5 = -6 + 5
w8=1\frac{w}{-8} = -1
* Multiply both sides by -8:
w8×(8)=1×(8)\frac{w}{-8} \times (-8) = -1 \times (-8)
w=8w = 8
Equation 2: 17=5k+217 = -5k + 2
* Subtract 2 from both sides:
172=5k+2217 - 2 = -5k + 2 - 2
15=5k15 = -5k
* Divide both sides by -5:
155=5k5\frac{15}{-5} = \frac{-5k}{-5}
3=k-3 = k
k=3k = -3
Equation 3: t3+4=10\frac{t}{3} + 4 = 10
* Subtract 4 from both sides:
t3+44=104\frac{t}{3} + 4 - 4 = 10 - 4
t3=6\frac{t}{3} = 6
* Multiply both sides by 3:
t3×3=6×3\frac{t}{3} \times 3 = 6 \times 3
t=18t = 18
Equation 4: 5=7+3r-5 = 7 + 3r
* Subtract 7 from both sides:
57=7+3r7-5 - 7 = 7 + 3r - 7
12=3r-12 = 3r
* Divide both sides by 3:
123=3r3\frac{-12}{3} = \frac{3r}{3}
4=r-4 = r
r=4r = -4

3. Final Answer

w=8w = 8
k=3k = -3
t=18t = 18
r=4r = -4