The problem asks to divide 182 by 51. This is represented as $182 \div 51$.

ArithmeticDivisionRemainderFractions
2025/4/14

1. Problem Description

The problem asks to divide 182 by
5

1. This is represented as $182 \div 51$.

2. Solution Steps

First, we estimate how many times 51 goes into
1
8

2. Since $50 \times 3 = 150$ and $50 \times 4 = 200$, we can estimate that 51 goes into 182 three times.

Now, we multiply 51 by 3:
51×3=15351 \times 3 = 153.
Next, we subtract 153 from 182:
182153=29182 - 153 = 29.
Since 29 is less than 51, we have found the quotient and the remainder. The quotient is 3, and the remainder is
2
9.
Therefore, 182÷51=3182 \div 51 = 3 with a remainder of 2929. We can also express this as 329513 \frac{29}{51}.

3. Final Answer

329513 \frac{29}{51}