Simplify the expression $\left(32x^{20}\right)^{-1/5}$, assuming that $x$ represents a positive real number.

AlgebraExponentsSimplificationAlgebraic Expressions
2025/4/15

1. Problem Description

Simplify the expression (32x20)1/5\left(32x^{20}\right)^{-1/5}, assuming that xx represents a positive real number.

2. Solution Steps

We want to simplify the expression (32x20)1/5\left(32x^{20}\right)^{-1/5}. We can use the property (ab)n=anbn(ab)^n = a^n b^n. Also, (am)n=amn(a^m)^n = a^{mn}.
(32x20)1/5=321/5(x20)1/5\left(32x^{20}\right)^{-1/5} = 32^{-1/5} (x^{20})^{-1/5}
Now, 32=2532 = 2^5.
321/5=(25)1/5=25(1/5)=21=1232^{-1/5} = (2^5)^{-1/5} = 2^{5(-1/5)} = 2^{-1} = \frac{1}{2}.
(x20)1/5=x20(1/5)=x4=1x4(x^{20})^{-1/5} = x^{20(-1/5)} = x^{-4} = \frac{1}{x^4}.
Therefore,
(32x20)1/5=121x4=12x4\left(32x^{20}\right)^{-1/5} = \frac{1}{2} \cdot \frac{1}{x^4} = \frac{1}{2x^4}.

3. Final Answer

12x4\frac{1}{2x^4}

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