The problem requires us to graph the exponential function $f(x) = 4 \cdot 2^x$.

AlgebraExponential FunctionsGraphingFunction EvaluationExponents
2025/4/17

1. Problem Description

The problem requires us to graph the exponential function f(x)=42xf(x) = 4 \cdot 2^x.

2. Solution Steps

To graph the function f(x)=42xf(x) = 4 \cdot 2^x, we need to find some points by plugging in different values of xx.
Let's calculate the values of f(x)f(x) for a few values of xx:
- If x=2x = -2, then f(2)=422=414=1f(-2) = 4 \cdot 2^{-2} = 4 \cdot \frac{1}{4} = 1. So, we have the point (2,1)(-2, 1).
- If x=1x = -1, then f(1)=421=412=2f(-1) = 4 \cdot 2^{-1} = 4 \cdot \frac{1}{2} = 2. So, we have the point (1,2)(-1, 2).
- If x=0x = 0, then f(0)=420=41=4f(0) = 4 \cdot 2^0 = 4 \cdot 1 = 4. So, we have the point (0,4)(0, 4).
- If x=1x = 1, then f(1)=421=42=8f(1) = 4 \cdot 2^1 = 4 \cdot 2 = 8. So, we have the point (1,8)(1, 8).
- If x=2x = 2, then f(2)=422=44=16f(2) = 4 \cdot 2^2 = 4 \cdot 4 = 16. So, we have the point (2,16)(2, 16).
- If x=3x = 3, then f(3)=423=48=32f(3) = 4 \cdot 2^3 = 4 \cdot 8 = 32. This is outside the range of the graph.
Now, we can plot these points and draw a smooth curve through them. The graph will increase rapidly as xx increases.

3. Final Answer

The graph of f(x)=42xf(x) = 4 \cdot 2^x passes through the points (2,1)(-2, 1), (1,2)(-1, 2), (0,4)(0, 4), (1,8)(1, 8), and (2,16)(2, 16). It is an exponential growth curve.

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