The problem asks to evaluate the following expressions: (a) $a^0 \times b^0$ (b) $x^0 + 2p^0 - a^0$ (c) $(\frac{x^0}{y^0})^{37}$ (d) $2a^0 \times 4b^0 \times 3c^0$

1. Problem Description

The problem asks to evaluate the following expressions:

(a) $a^0 \times b^0$

(b) $x^0 + 2p^0 - a^0$

(c) $(\frac{x^0}{y^0})^{37}$

(d) $2a^0 \times 4b^0 \times 3c^0$

2. Solution Steps

(a) $a^0 \times b^0$

Any non-zero number raised to the power of 0 is

1. So, $a^0 = 1$ and $b^0 = 1$.

$a^0 \times b^0 = 1 \times 1 = 1$

(b) $x^0 + 2p^0 - a^0$

Any non-zero number raised to the power of 0 is

1. So, $x^0 = 1$, $p^0 = 1$, and $a^0 = 1$.

$x^0 + 2p^0 - a^0 = 1 + 2(1) - 1 = 1 + 2 - 1 = 2$

(c) $(\frac{x^0}{y^0})^{37}$

Any non-zero number raised to the power of 0 is

1. So, $x^0 = 1$ and $y^0 = 1$.

$(\frac{x^0}{y^0})^{37} = (\frac{1}{1})^{37} = (1)^{37} = 1$

(d) $2a^0 \times 4b^0 \times 3c^0$

Any non-zero number raised to the power of 0 is

1. So, $a^0 = 1$, $b^0 = 1$, and $c^0 = 1$.

$2a^0 \times 4b^0 \times 3c^0 = 2(1) \times 4(1) \times 3(1) = 2 \times 4 \times 3 = 8 \times 3 = 24$

3. Final Answer

(a) 1

(b) 2

(c) 1

(d) 24