The problem is to perform the division $2345 \div 41$.

ArithmeticDivisionLong DivisionRemaindersInteger Arithmetic
2025/4/17

1. Problem Description

The problem is to perform the division 2345÷412345 \div 41.

2. Solution Steps

We perform long division:
\begin{enumerate}
\item Divide 234 by
4

1. We estimate that $41 \times 5 = 205$ and $41 \times 6 = 246$. Since $205 < 234 < 246$, we use 5 as the quotient.

\item Multiply 41 by 5 to get
2
0

5. Subtract 205 from 234 to get $234 - 205 = 29$.

\item Bring down the 5 to get
2
9

5. \item Divide 295 by

4

1. We estimate that $41 \times 7 = 287$.

\item Multiply 41 by 7 to get
2
8

7. Subtract 287 from 295 to get $295 - 287 = 8$.

\end{enumerate}
Thus, 2345=41×57+82345 = 41 \times 57 + 8.

3. Final Answer

2345÷41=572345 \div 41 = 57 with a remainder of 88. Therefore, the answer is 5784157 \frac{8}{41}.