The problem is a long division problem. We need to divide $4875$ by $21$ and find the quotient and remainder. The quotient is already partially computed as $231$. We need to complete the division to find the remainder.

ArithmeticDivisionRemainderInteger Arithmetic
2025/4/17

1. Problem Description

The problem is a long division problem. We need to divide 48754875 by 2121 and find the quotient and remainder. The quotient is already partially computed as 231231. We need to complete the division to find the remainder.

2. Solution Steps

The division is partially completed. Let's continue the process.
We have 4875÷214875 \div 21.
First step: 48÷21=248 \div 21 = 2, 2×21=422 \times 21 = 42, and 4842=648 - 42 = 6. Bring down the 77, so we have 6767.
Second step: 67÷21=367 \div 21 = 3, 3×21=633 \times 21 = 63, and 6763=467 - 63 = 4. Bring down the 55, so we have 4545.
Third step: 45÷21=245 \div 21 = 2. 2×21=422 \times 21 = 42. 4542=345 - 42 = 3.
So, 4875=21×232+34875 = 21 \times 232 + 3.
The quotient is 232232 and the remainder is 33.
The image already shows the first few steps. After subtracting 63 from 67, we get

4. Bringing down the 5, we have

4

5. The next digit in the quotient should be 2 since $21 \times 2 = 42$. Subtracting 42 from 45, we get

3. So the remainder is

3.

3. Final Answer

The remainder is 33.