The problem is to perform the division $5688 \div 21$ and find the quotient and the remainder.

1. Problem Description

The problem is to perform the division $5688 \div 21$ and find the quotient and the remainder.

2. Solution Steps

We perform long division.

First, we check how many times 21 goes into

5

6. $21 \times 2 = 42$

$21 \times 3 = 63$

So, 21 goes into 56 two times. We write 2 above the

6. $56 - 42 = 14$.

Bring down the 8 to make it

1

4

8. Now we check how many times 21 goes into

1

4

8. $21 \times 6 = 126$

$21 \times 7 = 147$

$21 \times 8 = 168$

So, 21 goes into 148 seven times. We write 7 above the

8. $148 - 147 = 1$

Bring down the last 8 to make it

1

8. Since 21 is larger than 18, 21 goes into 18 zero times. We write 0 after

2

7. Thus the quotient is 270 and the remainder is

1

8.

3. Final Answer

The quotient is 270 and the remainder is

1

8. $5688 = 21 \times 270 + 18$