The problem describes a piecewise function for electricity charges. For usage up to 1200 kWh, the charge is $7.10 plus 6.747$ cents per kWh. For usage exceeding 1200 kWh, the charge is $88.064$ plus $4.788$ cents per kWh above 1200 kWh. The problem asks to calculate the monthly charge for 910 kWh.

Applied MathematicsPiecewise FunctionsLinear EquationsWord ProblemElectricity ChargesUnit Conversion
2025/4/18

1. Problem Description

The problem describes a piecewise function for electricity charges. For usage up to 1200 kWh, the charge is 7.10plus6.7477.10 plus 6.747 cents per kWh. For usage exceeding 1200 kWh, the charge is 88.06488.064 plus 4.7884.788 cents per kWh above 1200 kWh. The problem asks to calculate the monthly charge for 910 kWh.

2. Solution Steps

Since the usage is 910 kWh, which is less than or equal to 1200 kWh, we use the first part of the piecewise function.
First, convert the cents to dollars: 6.7476.747 cents = 0.067470.06747 dollars.
The formula for the charge when x1200x \le 1200 is:
f(x)=7.10+0.06747xf(x) = 7.10 + 0.06747x
Plug in x=910x = 910:
f(910)=7.10+0.06747×910f(910) = 7.10 + 0.06747 \times 910
f(910)=7.10+61.3977f(910) = 7.10 + 61.3977
f(910)=68.4977f(910) = 68.4977
Round to two decimal places:
f(910)68.50f(910) \approx 68.50

3. Final Answer

68.5068.50

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