The problem is to divide $9567$ by $624$. We need to find the quotient and the remainder.

1. Problem Description

The problem is to divide $9567$ by $624$. We need to find the quotient and the remainder.

2. Solution Steps

We perform long division.

* First, we see how many times $624$ goes into $956$. Since $624 \times 1 = 624$ and $624 \times 2 = 1248$, $624$ goes into $956$ once. So the first digit of the quotient is $1$. We write $1$ above the $6$ in $9567$.

$956 - 624 = 332$.

* Next, we bring down the $7$ from $9567$ to get $3327$.

* We see how many times $624$ goes into $3327$.

$624 \times 5 = 3120$

$624 \times 6 = 3744$

So $624$ goes into $3327$ five times. We write $5$ next to the $1$ in the quotient.

$3327 - 3120 = 207$.

* The quotient is $15$ and the remainder is $207$.

$$$$

\begin{array}{c|cc cc}

\multicolumn{2}{r}{1} & 5 \\

\cline{2-5}

624 & 9 & 5 & 6 & 7 \\

\multicolumn{2}{r}{6} & 2 & 4 \\

\cline{2-4}

\multicolumn{2}{r}{3} & 3 & 2 & 7 \\

\multicolumn{2}{r}{3} & 1 & 2 & 0 \\

\cline{3-5}

\multicolumn{2}{r}{} & 2 & 0 & 7 \\

\end{array}

$$$$

3. Final Answer

The quotient is 15 and the remainder is

2

0

7. So, $9567 \div 624 = 15$ with a remainder of $207$.