The problem is to solve the long division problem: $9567 \div 646$. The image shows the initial steps of the long division.

ArithmeticDivisionLong DivisionRemainders
2025/4/19

1. Problem Description

The problem is to solve the long division problem: 9567÷6469567 \div 646. The image shows the initial steps of the long division.

2. Solution Steps

First, we need to determine how many times 646 goes into
9
5

6. The provided work shows that 646 goes into 956 once, so we write '1' above the 6 in

9
5
6
7.
Then we multiply 1 by 646, which is
6
4

6. We subtract 646 from

9
5

6. $956 - 646 = 310$.

Now, bring down the 7 from 9567, resulting in
3
1
0

7. We need to find out how many times 646 goes into

3
1
0

7. Estimate: $3100 \div 600$ is approximately

5.
Now multiply 646×4=2584646 \times 4 = 2584.
Multiply 646×5=3230646 \times 5 = 3230. This is bigger than 3107 so 4 is the right answer.
So 646 goes into 3107 four times. Write 4 above the 7 in
9
5
6

7. $646 \times 4 = 2584$.

31072584=5233107 - 2584 = 523.
The quotient is 14, and the remainder is
5
2
3.

3. Final Answer

9567÷646=149567 \div 646 = 14 with a remainder of 523523.
So, the answer is 14R52314 R 523.

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