The problem asks us to evaluate the cube root of -729, i.e., find the value of $\sqrt[3]{-729}$. We need to determine if the cube root is a real number, and if so, find its value.

ArithmeticRootsCube RootInteger Arithmetic
2025/4/20

1. Problem Description

The problem asks us to evaluate the cube root of -729, i.e., find the value of 7293\sqrt[3]{-729}. We need to determine if the cube root is a real number, and if so, find its value.

2. Solution Steps

We are looking for a number xx such that x3=729x^3 = -729.
We know that 93=9×9×9=81×9=7299^3 = 9 \times 9 \times 9 = 81 \times 9 = 729.
Therefore, (9)3=(9)×(9)×(9)=81×(9)=729(-9)^3 = (-9) \times (-9) \times (-9) = 81 \times (-9) = -729.
So, 7293=9\sqrt[3]{-729} = -9.

3. Final Answer

The cube root of -729 is -

9. So, the answer is: $\sqrt[3]{-729} = -9$.

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