The problem describes a rectangle made of 8 rods of length 12 cm each. The rectangle has 3 rods on the long side (length) and 1 rod on the short side (width). We are asked to find the minimum length and perimeter of this rectangle. In the second part of the problem, we are given rainfall data for the town Rundu. In part (a), the annual rainfall in 2003 was 470 mm. The rainfall in 2004 was 16% more than in 2003. We are asked to find the annual rainfall in 2004. In part (b), we are given that the rainfall in 2003 (470 mm) was 29% more than in 2002. We are asked to find the annual rainfall in 2002.

1. Problem Description

The problem describes a rectangle made of 8 rods of length 12 cm each. The rectangle has 3 rods on the long side (length) and 1 rod on the short side (width). We are asked to find the minimum length and perimeter of this rectangle.

In the second part of the problem, we are given rainfall data for the town Rundu. In part (a), the annual rainfall in 2003 was 470 mm. The rainfall in 2004 was 16% more than in

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3. We are asked to find the annual rainfall in

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4. In part (b), we are given that the rainfall in 2003 (470 mm) was 29% more than in

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2. We are asked to find the annual rainfall in

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2. Solution Steps

(a) Length of the rectangle:

Since the rectangle's length is made of 3 rods, and each rod is 12 cm long, the length of the rectangle is:

$Length = 3 \times 12 = 36$ cm

(b) Perimeter of the rectangle:

The length of the rectangle is 36 cm. The width of the rectangle is made of 1 rod, so the width is 12 cm.

The formula for the perimeter of a rectangle is:

$Perimeter = 2 \times (Length + Width)$

$Perimeter = 2 \times (36 + 12)$

$Perimeter = 2 \times 48$

$Perimeter = 96$ cm

(c) Rainfall in 2004:

The rainfall in 2004 was 16% more than in 2003, which was 470 mm.

So, the rainfall in 2004 is:

$Rainfall_{2004} = Rainfall_{2003} + 0.16 \times Rainfall_{2003}$

$Rainfall_{2004} = 470 + 0.16 \times 470$

$Rainfall_{2004} = 470 + 75.2$

$Rainfall_{2004} = 545.2$ mm

(d) Rainfall in 2002:

The rainfall in 2003 was 29% more than in

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2. Let the rainfall in 2002 be $x$. Then:

$470 = x + 0.29x$

$470 = 1.29x$

$x = \frac{470}{1.29}$

$x \approx 364.34$ mm

3. Final Answer

(a) The minimum length of the rectangle is 36 cm.

(b) The minimum perimeter of the rectangle is 96 cm.

(c) The annual rainfall in 2004 was 545.2 mm.

(d) The annual rainfall in 2002 was approximately 364.34 mm.