The problem asks to solve the following system of equations: $y = -x + 3$ $x + y = -\frac{5}{2}$ by graphing and finding the intersection point.

AlgebraSystems of EquationsLinear EquationsGraphingParallel LinesNo Solution
2025/3/17

1. Problem Description

The problem asks to solve the following system of equations:
y=x+3y = -x + 3
x+y=52x + y = -\frac{5}{2}
by graphing and finding the intersection point.

2. Solution Steps

First, rewrite the second equation in slope-intercept form, y=mx+by = mx + b:
x+y=52x + y = -\frac{5}{2}
y=x52y = -x - \frac{5}{2}
Now we have two equations in slope-intercept form:
y=x+3y = -x + 3
y=x52y = -x - \frac{5}{2}
The first equation has a slope of 1-1 and a y-intercept of 33.
The second equation has a slope of 1-1 and a y-intercept of 52=2.5-\frac{5}{2} = -2.5.
Since the slopes are equal, the lines are parallel. Therefore, they do not intersect.

3. Final Answer

Since the two lines are parallel, there is no solution to the system of equations.
The two lines do not intersect.
No solution.