The problem asks us to find the distance between home and office, given that walking at 4 km/h takes 30 minutes longer than walking at 5 km/h.

AlgebraDistanceSpeedTimeLinear EquationsWord Problem
2025/4/22

1. Problem Description

The problem asks us to find the distance between home and office, given that walking at 4 km/h takes 30 minutes longer than walking at 5 km/h.

2. Solution Steps

Let dd be the distance between the house and the office in kilometers.
Let t1t_1 be the time it takes to walk at 4 km/h, and t2t_2 be the time it takes to walk at 5 km/h.
We are given that t1=t2+30 minutest_1 = t_2 + 30 \text{ minutes}. We need to convert the minutes into hours by dividing by 60, thus
t1=t2+3060=t2+12t_1 = t_2 + \frac{30}{60} = t_2 + \frac{1}{2} hours.
We know that distance = speed * time, so we have:
d=4t1d = 4t_1
d=5t2d = 5t_2
From the first equation, we have t1=d4t_1 = \frac{d}{4}.
From the second equation, we have t2=d5t_2 = \frac{d}{5}.
Substituting these into the equation t1=t2+12t_1 = t_2 + \frac{1}{2}, we get
d4=d5+12\frac{d}{4} = \frac{d}{5} + \frac{1}{2}
Multiplying both sides by 20, we get:
5d=4d+105d = 4d + 10
5d4d=105d - 4d = 10
d=10d = 10
Therefore, the distance between the house and the office is 10 km.

3. Final Answer

The distance between my house and office is 10 km.

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